$C_{2}H_{13}N$ Nreacts with HN02 to give an optically active alcohol. What is this compound?
Give its IUPAC name.
HN02 reacts with C_{5}H_{13}N to give an alcohol means the compound is primary amine.
C_{5}H_{13}N means C_{5}H_{11}N{ H }_{ 2 }
Optically active alcohol means C_{5}H_{11}OH segment contain a chiral carbon.