Volume at n.t.p of 0.22 g of co2 is same as :

_{2}

gas =22.4L

Mass of 1 mole of CO_{2}

gas= 44g

44g of gas= 22.4L

therefore 0.22g of gas = 0.22/44 moles= 0.005 moles

Volume= (22.4/44) X 0.22L= 0.112L

similarly

Molar mass of hydrogen gas = 2g

0.01 g of hydrogen gas = 0.01/2= 0.005 moles

Therefore volume = 22.4X 1/200 = 0.112L

Molar mass of ammonia= 17 g

0.085g= 0.085/17=0.005 moles

1 mole - 22.4 L

therefore 0.005 moles = 0.112 L

Molar mass of SO_{2}

= 64g

320mg= 0.32 g= 0.32/64 = 0.005 moles

1 mole - 22.4 L

therefore 0.005 moles = 0.112 L

Hence all of the above are correct