Using the VSEPR theory identity the type of hybridization and draw the structure of O${{F}_{2}}$. What are oxidation states of O and F?

Electron dot structure of O${{F}{2}} is <img src="/uploads/db3785/original/1X/1a0bcc69603ffcba1d0381b5d1ef265d8f0ab355.png" width="313" height="98"> Thus the central atom (O-atom) has 4 pairs of electrons (2 bond pairs and 2 lone pairs). Hence oxygen in O{{F}{2}} is s{{p}^{3}}$ hybridised and the molecule is v-shaped. Oxidation sTate" of F = - 1, oxidation state of O = + 2.