Using RHS congruence rule, prove that ∆ABC is an isosceles triangle

BE and CF are two equal altitudes of a ∆ABC. Using RHS congruence rule, prove that ∆ABC is an isosceles triangle.
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Given In ∆ ABC, BE = CF and ∠BFC =∠CEB = 90°
To prove ∆ ABC is an isosceles triangle.
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Proof In ∆BEC and ∆CFB
BE =CF
∠ BEC = ∠ CFB
and BC = BC
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⇒ ∠ ECB =∠ FBC '[byCPCT]
or ∠ ACB =∠ ABC
⇒ AB = AC
∆ ABC is an isosceles triangle.