The sum of a two-digit number and the number obtained by reversing the order of its digits is 121. If unit’s and ten’s digits of the number are x and y respectively, then write the linear equation representing the above statement.
Given, unit’s digit is x and ten’s digit is y.
Then, number = 10y + x
and new number after reversing the digits
= 10x +y
According to the question,
10y+x +10x+y = 121 (1/2)
= 11x + 11y = 121
=x+y = 11 [dividing both sides by 11]
Which is the required linear equation.