The sum of a two-digit number and the number obtained by reversing the order of its digits is 121. If unit’s and ten’s digits of the number are x and y respectively, then write the linear equation representing the above statement.

Given, unit’s digit is x and ten’s digit is y.

Then, number = 10y + x

and new number after reversing the digits

= 10x +y

According to the question,

10y+x +10x+y = 121 (1/2)

= 11x + 11y = 121

=x+y = 11 [dividing both sides by 11]

Which is the required linear equation.