The length, breadth and thickness of a rectangular

sheet of metal are 4.234 m, 1.005 m and 2.01 cm respectively. Give the area and volume of the sheet to correct significant figures.

Given, length (l) = 4.234 m

Breadth (b) = 1.005 m

Thickness (t) = 2.01 cm = 0.0201 m

Area of sheet (A) = 2(lx b + b x t +t x l)

= 2 [(4.234 x 1.005) + (1.005 x 0.0201)

’ +(0.0201x4.234)]

= 2 x 43604739

= 8.7209478 ${{m}^{2}}$

As thickness has least number of significant figures 3, therefore rounding off area up to three significant figures, we get

Area of sheet (A) = 8.72 ${{m}^{2}}$

Volume of sheet (V) = Ix bx t

= 4.234x1.005 x 0.0201 = 0.0855289

Rounding off up to three significant figures, we get Volume of the sheet = 0.0855${{m}^{3}}$