The atomic number of iron is 26 Its electronic configuration =2 8 8 8 Then how its valency is 2+ and3+

The atomic number of iron is 26
Its electronic configuration =2 8 8 8
Then how its valency is 2+ and3+

Iron does not have 8 valence electrons, it only has 2, here’s why.

Oxidation state depends upon the valence electrons and valence electrons are the electrons present in the outer most shell of an atom

For Fe, n=4, N shell,

In Iron the electronic configuration of Fe = 1s2 2s2 2p6 3s2 3p64s2 3d6 from the electronic configuration and the below diagram you may have a clear idea about valence electrons in the Fe

i.e., Iron has only 2 valence electrons.

For Fe when two 4s electrons are removed, it has a +2 oxidation state and electronic configuration of Fe+2 = 1s2 2s2 2p6 3s2 3p6 3d6

Now, the n=3 becomes the outer most shell, iron can lose electrons from this shell as well more specifically from the 3d subshell which has 6 electrons.

when one electron from 3d subshell s removed, iron has a +3 oxidation state and

electronic configuration of Fe+3 = 1s2 2s2 2p6 3s2 3p6 3d5

+2 and +3 are the common oxidation states of Iron.