solve the following equations by trial and error method: 5p+2=17

5p + 2 = 17

Consider, x = 1

Then LHS = 5 × 1 + 2 = 7

LHS ≠ RHS

Hence, p = 1 is not a solution.

Consider,

p = 3

LHS = 5 × 3 + 2 = 17

LHS = RHS

Hence, p = 3 is a solution of the given equation.