Molar volume is the volume occupied by 1 mol of any (ideal) gas at standard temperature and pressure (STP: 1 atm pressure, 0°C). Show that it is 22.4 L.
As, for one mole of ideal gas, pV = µRt
pV = RT
V = RT / p
Putting , R = 8.31 J ${{mol}^{-1}}$ ${{K}^{-1}}$ , T = 273 K
p= 1 atm = 1.013 x ${{10}^{5}}$ N-${{m}^{-2}}$
V = 8.31 x 273 / 1.013 x ${{10}^{5}}$ = 0.0224 ${{m}^{3}}$
= 0.0224 x ${{10}^{6}}$ cc
22400 cc = 22.4L