It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

As the probability of 2 students not having the same birthday, P (not E) – 0.992

∴ Probability of students having the same birthday,

P(E) = 1 – P(not E) = 1 – 0.992 = 0.008