In triangle ABC, AD is a median and E is a midpoint of median AD. A line through B and E meets AC at point F. Prove that AC=3AF

For helpwe drawa line DG//BF

Now from triangle ADG. DG// DF and E is the midpoint of AD

Therefoce F is the midpoint of AG.ie AF=GF (1)

From triangle BCF, DG//DF and D is the midpoint of BC

Therefore G is the midpoint of CF,ie GF=CF …(2)

AC=AF+GF+CF

AC=3AF(From (1) and (2))

Hence proved