In the given figure, if ∠POQ = 80°, then find ∠PAQ and ∠PCQ.

Given, ∠POQ = 80°

From the given figure, we have ∠POQ =2 x ∠PAQ

[∴ angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle]

Now ∠PCQ =∠PAQ

[ ∴ angle in the same segment are equal]

∠PCQ = 40°