In preparing solution of a given concentration from solution of varying concentration, the following formula is used i.e M1V1+M2V2=M3V3.what volume of 6M HCl and 2M HCl should be mixed to prepare 1000ml of 3M HCl?

Let us suppose that the volume of 6 M HCl (V_{1}) = x L

Therefore, the volume of 2 M HCl required to make 1 L of 3 M HCl (V_{2}) = (1- x) L

Let us take M_{1} = 6M and M_{2} = 2M,

As given, we know that, Molarity of a mixture is given by the equation:

Therefore, Volume of 6M HCl = 0.25L

and Volume of 2 M HCl = 1-0.25 = **0.75 L**