In class IX of 50 students second language opted by the students is as follows Sanskrit -14, Japanese -08, French -12, Urdu -6.

Rest of them opted for German.

A student is selected at random. Find the probability that the student

(i) opts for French.

(ii) does not opts for Japaness.

(iii) Either opts for Sanskrit or German.

∵ Total numbers of students = 50 [given]

∴ Total numbers of trial = 50

(i) Probability that a student selected is opts French language = 12/50 = 6/25

(ii) Probability that a student selected does not opt for Japaness

= 1 - selected students opts Japaness

(iii) Probability that selected student either opts for Sanskrit or for German = Probability of students opts Sanskrit + Probability of students opts German

∴ Number of students who opted German

= 50-(14+ 8+12 + 6)

= 50-40 = 10