In ∆ABC, the bisectors of ∠B and ∠C intersect each other at a point O. Prove that

∠BOC = 90°+ 1/2 ∠A.

Given In ∆ABC, OS and OC are the angle bisectors of∠ABC and ∠ACB, respectively.

∠BOC = 90°+ 1/2 ∠A.

Given In ∆ABC, OS and OC are the angle bisectors of∠ABC and ∠ACB, respectively.