If a current of 0.5 A flows through a metallic wire for 2 h, then how many electrons would flow through the wire?

Here, current, i = 0.5 A, time, t = 2 h

Quantity of charge (Q) passed = Current (i) X Time (t)

= (0.5A)x(2x 60x60s)

= 3600 A s = 3600 C

Again, Q=${{ne}^{-}}$

where, n = number of electrons,

${{e}^{-}}$= charge on electron

n = Q/${{e}^{-}}$ = 3600C/1.6 x ${{10}^{-19}}$C

= 2250 x${{10}^{19}}$

Thus, number of electrons = 2.250 X${{10}^{22}}$