If a 12V’battery is connected to the arrangement of resistances given below; calculate:

(i) the total effective resistance of the arrangement and,

(ii) the total current flowing in the circuit.

(i) The 5Ω resistors are connected in series.

Therefore, their effective resistance = (5 +5) = 1OΩ

The 10Ω resistors are connected in series.

Therefore, their effective resistance = (10 + 10) = 20Ω

Now, these 10Ω equivalent and 20Ω equivalent are connected in parallel. Therefore,

the equivalent resistance (Req) will be

(ii)Total current = Total Voltage/Total equivalent resistance

= 12/6.67= 1.8A