If 0.5 mole of BaCl2 is mixed with 0.2 mole of Na3PO4,

CBSE Class 11
1

If 0.5 mole of BaCl2 is mixed with 0.2 mole of Na3PO4, the maximum no. of mole of NaCl that can be formed is

2

Balanced equation for reaction between BaCl2 and Na3PO4 is as follows:
3BaCl2 + 2Na3PO4 → Ba3(PO4)2 + 6NaCl
3 moles of BaCl2 react with 2 moles of Na3PO4 to give 1 mole of Ba3(PO4)2
0.5 moles of BaCl2 will react with (2/3) x 0.5 = 0.33 moles of Na3PO4
Available moles of Na3PO4 = 0.2
So, Na3PO4is the limiting reagent
Now, 2 moles of Na3PO4 give 1 mole of Ba3(PO4)2
So, 0.2 moles of Na3PO4 will give ½ x 0.2 = 0.1 mole of Ba3(PO4)2
Hence, maximum number of moles of Ba3(PO4)2 formed = 0.1