3H2(g) + N2(g)→2NH3(g)
How many moles of NH3 can be produced from 24.0 mol of H2 and excess N2?
Answer:
3H2(g) + N2(g)→2NH3(g)
according to balanced reaction
3 moles of H2 gives 2 moles of NH3
24.0 moles of H2 gives (24 x 2) /3 = 16
moles of NH3 formed = 16