**For a test of Ho: p = 0.5, the z test statistic equals 1.52. Find the p-value for Ha: p does not equal 0.5.**

**Answer:**

p value = 0.1286

Since we have a two-tailed test, the P-value is the probability that the z statistic is less than - 1.52 or greater than 1.52.

We use the z Distribution Calculator to find P(t < - 1.52) = 0.0643, and P(t > 1.52) = 0.0643

Thus, the P-value = 0.0643 + 0.0643 = 0.1286

Interpret results. Since the P-value (0.1286) is greater than the significance level (0.05), we cannot reject the null hypothesis.

From the test we conclude that we have sufficient evidence to support the claim that p = 0.5.