Two ions having 3 negative and 3 positive charges are found to have 7 and 14 neutrons respectively. If electronic configuration of these ions are similar to that of neon (Ne), then find the mass number of both the ions.
The electronic configuration of Ne= 2, 8
Atom, which forms ion with 3 positive charges, will have electronic configuration as = 2, 5(K,L)
Hence, the given atom is nitrogen.
Mass number = Number of protons + number of neutrons = 7 + 7 = 14
Similarly, atom which forms ion with 3 negative charges, will have electronic configuration as = 2, 8, 3 (K,L,M)
Hence, the given atom is aluminium.
Mass number = Number of protons + number of neutrons
= 13 + 14 = 27