Find the difference in the oxidation numbernumbers present of the two

Find the difference in the oxidation numbers present of the two types of sulphur present in Na2S4O6 [sodium - 2 sulphur - 4 oxygen - 6].
(Hint :- sulphur-sulphur linkages present)

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In the case of Na2S4O6, if we observe the structure of this compound it is found that there are two types of sulphur atoms

  1. O.S. of first sulphur: sulphur is attached to the same sulphur atoms hence there is no change in the electronic arrangement of this sulphur atom, therefore, its O.S. is zero.
  2. O.S. of second sulphur: This atom of sulphur is attached to the three oxygen atoms two are doubly bonded and one is singly bonded
    Therefore for doubly bonded oxygen will exert the charge +2 and for singly bonded oxygen will +1. hence on total, the O.S. of Second sulphur is +5.