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Find the area of the surface z = 2/3(x^3/2+y^3/2), 0≤x≤1, 0≤y≤1
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Dhanalakshmi
May 31, 2019, 6:30am
1
Find the area of the surface z=2/3(x
3/2
+y
3/2
), 0≤x≤1, 0≤y≤1