Construct a ∆ABC in which BC = 4.6 cm, ∠B =45° and AB + CA =8.2 cm.

Given, BC = 4.6 cm, ∠B = 45“ and AB + CA = 8.2 cm

In horizontal axis take 1 block is equal to 10 units and in vertical axis, take 1 block is equal to 5 units.

Steps of construction

(i) Draw the base line segment BC = 4.6 cm.

(ii) At the point S, make ∠XBC = 45“.

(iii) Now, cut a line segment BD equal to AB + AC = 8.2 cm from the ray BX.

(iv) Join DC.

(v)Draw perpendicular bisector MN of CD which meets BX at A.

(vi)On joining AC, we get the required ∆ABC