Conical tent is made of 4.5 m wide tarpaulin. Vertical height of the conical tent is 4 m and base radius is 3 m. Find the length of the tarpaulin used, assuming that 10% extra material is required for stitching margins and wastage in cutting (Take π = 3.14)

r = 3m, h=4m

l = Square root of (r^{2}+h^{2}) = 5m

CSA=πrl = 47.10m^{2}

Area la extra material (10%) = (10/100) × 47.10

= 4.71m^{2}

Total are = 47.10 + 4.71 = 51.81m^{2}

Breadth is given 4.5m

Length = ?

Area = l × b

51.81 = l × 4.5m

l=11.51