Compare the frequencies of note A and C played during a musical concert when the speed of sound is 340 m${{s}^{-1}}$ and wavelength of A and C are 1.5 m and 1.33 m, respectively.
As we know that, from the relation, v = v$\lambda $
Frequency of the sound wave (v) = Speed of sound / Wavelength of sound
So, frequency of note A, ${ V }_{ A }$ = 340/1.5= 226.66 Hz
Again, frequency of note C,${ V }_{ c }$ = 340/1.33 = 255.63 Hz
So, frequency of note C is more than frequency of note A