Calculate the volume occupied by 8.8 g of $CO_{ 2 }$ at 31.1° C and 1 bar pressure. R = 0.083 bar L ${{K}^{-1}}$${{mol}^{-1}}$
pV = nRT or pV = m/M RT
Volume occupied by 8.8 g of $CO_{ 2 }$,
V = mRT/pM
= 8.8g x 0.083 bar L ${{K}^{-1}}$${{mol}^{-1}}$ x
304.1 K/ 1 bar x 44 g ${{mol}^{-1}}$
V = 5.048 L