Calculate the number of molecules of $S{{O}_{2}}$ present in 44 g of it.

Number of molecules in 64 g of S02 = NA =6.022 x ${10}^{23}$

Number of molecules in 44 g of S02 = 6.022 x ${10}^{23}$ / 64 g x 44 g

= 4.14 x ${10}^{23}$

Calculate the number of molecules of $S{{O}_{2}}$ present in 44 g of it.

Number of molecules in 64 g of S02 = NA =6.022 x ${10}^{23}$

Number of molecules in 44 g of S02 = 6.022 x ${10}^{23}$ / 64 g x 44 g

= 4.14 x ${10}^{23}$