The standard electrode potential (E°) for Daniell cell is +1.1 V. Calculate, the ∆G° for the reaction.
Zn(s) + ${{Cu}^{2+}}$(aq) > ${{Zn}^{2+}}$(aq) + Cu(s)
(1 F= 96500 C ${{mol}^{-1}}$)
Zn(s) + ${{Cu}^{2+}}$(aq) > ${{Zn}^{2+}}$(aq) + Cu(s)
${ E }^{ 0 }$ = + 1.1 V,∆G° = ?
1F = 96500 C ${ mol }^{-1}$, n= 2
∆G° = $-nF{ E }^{ 0 }$ = -2 x 96500 x 1.1
= -212300 J ${ mol }^{-1}$