Calculate molar mass of ethanol and number of hydrogen atoms present in 2.3 g of it
Ethanol (C2H5OH)
Molecular weight calculation:
12.0107 + 1.007943 + 12.0107 + 1.007942 + 15.9994 + 1.00794
= 46.06844 g/mol
Calculation hydrogen atoms in 2.3g of ethanol
Thus 2.3 g / 46 g / mol = 0.05 moles
0.05 moles * 6.02 x 10E23 molecules per mole (Avogadro number) = 30100000000000000000000 molecules of C2H5OH
Thus, as you have 6 atoms of hydrogen per molecule, you have then 6 * 30100000000000000000000 =
180600000000000000000000 atoms of hydrogen