Atomic number of aluminum is 13 and mass no. is 27. calculate number of the electrons, protons, and neutrons in the ion formed. represent the ion. what will be its valency?
Aluminum has valency 3+
At the beginning,
Number of electrons is 13
Number of protons is 13
Number of neutrons is 27-13=14
After Ion the formation,
Al → Al3+ + 3e-
the number of
Electrons are 13-3 =10
Protons are 13
Neutrons are 14