Assuming that the two diodes used in the electric circuit as shown in the figure are ideal, find out the value of the current flowing through 1 Ω resistor.
According to the question,
Equivalent resistance, { R }_{ AB } = 2 + 1 = 3Ω
1/R’ = 1/2 + 1/3 = 3+2/6 = 5/6 Ω
R’ = 6/5 Ω
{ I}_{ EF } = V/R’ = 6/6/5 = 5A