An electric iron has a rating of 750W, 220V. Calculate.

(i) Current passing through it, and

(ii) Its resistance, when in use.

(i) Power = Voltage × Current

Let, the current passing through the bulb be I

Therefore, 3.41 A current passes through the electric iron.

(ii) Electric power is related to voltage and resistance as:

It is given that, the rating of the electric bulb is 750W, 220V.

Therefore, the electric iron offers 64.53Ω resistance when in use.