An 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000N & the track offers a friction force of 5000 N. Calculate

a) the net accelerating force,

b) the acceleration of the train, and

c) the force of wagon 1 on wagon 2.

# An 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along

a) Net accelerating force = 40000 - 5000 = 35000 N

b) Acceleration = Force/Mass = 35000/(8000 + 5x2000) = 1.94 m/s^{2}

c) Letâ€™s imagine the wagon 1 and engine detached, and a force p is included to account for the detachment.

Then the net force acting, p which is acting from wagon 2 onto 1 and is same as acting from 1 to 2.

p = ma = (8000 + 2000) (1.94) = 19400 N.

Hence the force of wagon 1 on 2 is 19400 N.