ABCD is a rectangle with ∠BAC = 32°. Determine ∠DBC

ABCD is a rectangle with ∠BAC = 32°. Determine ∠DBC.
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Angle Suppose the diagonals AC and BD intersect at O.
Then, in ∆ OAB, we have
OA = OB [ diagonals of rectangle are equal and they bisect each other]
∠OAB =∠OBA
∠BAC=∠DBA
∠DBA = 32° [∠BAC = 32°(given)]
Now,
∠ABC = 90°
∠DBA +∠DBC = 90°
32° +∠DBC = 90°
∠DBC = 90° - 32° = 58°