A wire of length 2.5 m has a percentage strain of 0.012%

CBSE Class 11 CBSE Class 11 Physics
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1

A wire of length 2.5 m has a percentage strain of 0.012% under a tensile force. Determine the extension in the wire.

2

Here, original length, L = 2.5 m
Strain =∆L/L = 0.012% = 0.012/100

∆L = Strain x L

or ∆L = extension = 0.012 / 100 x L
= 0.012 x 2.5/100 = 3 x ${{10}^{-4}}$ m = 0.3 mm