A train is traveling at a speed of 90km/hr. breaks are applied so as to produce a uniform acceleration of -o.5meter per second square. find how far will the train go before it is brought into rest?

Initial speed, u = 90 km/h = 90 x (1000/3600) m/s = 25 m/s

final speed, v = 0 m/s

uniform acceleration, a = -0.5 m/s^{2}

Using equation of motion: v^{2} = u^{2} + 2as

We have: 0 = (25)^{2} + 2x(-0.5)xs

s = 625 m

[s: distance traveled by the train after the brakes are applied and before it is finally brought into rest]