A stone is thrown in a vertically upward direction with a velocity of 5 m/s.if the acceleration of the stone during the motion is 10 m/s in the downward direction, what will be the height attained by the stone and how much time will it take to reach there.

To find the height attained,

v^{2} = u^{2} + 2as

s = Height attained = (v^{2} - u^{2})/2a = (0 - 25)/(2 x -10) = 1.25 .

a is negative since itâ€™s direction is opposite to the direction of motion.

t = (v - u)/a = -5/-10 = 0.5 s.