Let the two bodies have masses m1 and m2 respectively such that m2 > m1 . Then, for first object p1 = m1v1 and for second object p2 = m2v2

But p1 = p2 or m1v1 = m2v2

Since m1 < m2, then v1 > v2

Now, K = 1/2 mv^2 = 1/2 pv, therefore,

K1/K2 = p1v1 / p2v2 = v1/v2

But v1 > v2

Therefore, kinetic energy of body of lesser mass is more.

Let m1 and m2 be the masses of the light and heavy objects respectively

We know that, K.E= p^2/2m

Therefore, K.E of light object= p^2/2m1

of heavy object= p^2/2m2

So, ratio- K.E1/K.E2

= p^2/2m1 * 2m1/p^2

P^2 gets cancelled as objects have same momentum

2 also gets cancelled

= m2/m1

Therefore ratio of their kinetic energies = mass of heavy object : mass of light object

Now K.E = 1/2mv^2

Therefore, K.E is directly proportional to mass.

Hence, K.E of heavy object will be greater than that of the light object

Prasanna you are wrong because you cannot take mv^2 as p

Because it is m* v^2

And not (mv)^2

@Vmking123 prasanna is correct because v^2 can also be written as v x v and (mv) can be considered as a bracket