A field is in the shape of given figure, in which ABCD is a rectangle and the triangles APB, BCQ, CDR and ADS, whose make out side of rectangle are equilateral. Find the area of field.

From the given figure.

sides of the rectangle are 8 cm and 6 cm.

[∵ area of rectangle = length x breadth]

Side of triangles APB and CDR is 8 cm.

Side of triangles BCQ and ADS is 6 cm.

Now, area of field=Area of rectangle ABCD+ Area of ∆ APB + Area of ∆BCQ + Area of ∆CDR + Area of ∆ ADS

= 48+16√3 +9√3 +16√3+9√3