A cricketer can throw a ball to a maximum horizontal distance of 100 m. how much high above the
We know that horizontal range is maximum if the angle of projection is 45o and is given by
Rmax = u2 / g
Here, Rmax = 100 m
so, u2 / g = 100 m
If the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the ground
Hmax = u2 / 2g = 100 /2 = 50 m.