Let the events E1 E2 E3, E4 and A be defined as follows:

E_{1}: Missing card is a diamond

E_{2}: Missing card is a spade

E_{3}: Missing card is a club

E_{4}: Missing card is a heart

A: Drawing two club cards

P(E_{1}) = P( E_{2}) = P( E_{3})=P( E_{4}) =1/4

Total number of bulbs = 10

Number of defective bulbs = 3

Number of non defective bulbs = 7

P(drawing a defective bulb) ,p =3/10

P(drawing a non defective bulb),q =7/10

Two bulbs are drawn let X denotes the number of defective bulbs then X can take values 0, 1, 2

P(X = 0) = P(drawing both non defective bulbs) =(7/10)^{2}

P(X = 1) = P(drawing one defective and one non defective bulb)

= P (drawing a non defective bulb and a defective bulb) + P (drawing a

defective bulb and a non defective bulb)

=

P(X = 2) = P(drawing both defective bulbs)=(3/10)^{2}

Required Probability distribution is