A body of mass 500g moving with 10ms^{-1} increases to 20ms^{-1} when acted upon a force. Find

(i) the change on Kinetic Energy

(ii) the work done by the force

(iii) name the theorem based on the same

(i) Change in kintic energy = (1/2)mv_{f}^{2} - (1/2)mv_{i}^{2} = (1/2)×0.5×( 20^{2} - 10^{2} ) = 300 J

(ii) Workdone by the force = 300 J

(iii) Theorem used is " Work-Energy Theorem "