A body is thrown vertically upwards with an initial velocity u reaches the maximum height in 6s. The ratio of the distance traveled by the body in first second to seventh second is_______.

Initial velocity u = g×t = 9.8×6 = 58.8 m/s

distance S1 travelled in first second is calculated using " S = u×t - (1/2)×g×t^{2} ", using u = 58.8 m/s, and t = 1 s;

S1 = 58.8×1 -(1/2)×9.8×1= 53.9 m

Since the particle reaches maximum height in 6 s, at 7th second travel, its initial velocity is zero.

hence distance S_{7} travelled in 7th second = (1/2)×9.8×1×1 = 4.9 m

hence the ratio S_{1} / S_{7} = 53.9 / 4.9 = 11