A body covers 12m in the second second and 20m in the 4th second. what distance the body will cover in 4s after the 5th second?

Thus distance traveled in 2nd second is Sā = 12 = distance traveled between 2nd and 1st second i.e

and Similarly

Sāā = 20 =distance between 20th and 19th second

Solving these two equations simultaneously we get:

u= 34/3

a= 4/9

and now S= distance traveled in 9th second and 8th second according to the question.

thus S= 136/9