A body covers 12m in the second second and 20m in the 4th second. what distance the body will cover in 4s after the 5th second?
Let initial velocity be u and acceleration be a.
Thus distance traveled in 2nd second is S’ = 12 = distance traveled between 2nd and 1st second i.e
and Similarly
S’’ = 20 =distance between 20th and 19th second
Solving these two equations simultaneously we get:
u= 34/3
a= 4/9
and now S= distance traveled in 9th second and 8th second according to the question.
thus S= 136/9