A 44 mH inductor is connected to 220 V, 50 Hz AC supply. Determine the rms value of the current in the circuit. What is the net power absorbed over a complete cycle? Explain.

Given , inductance = 44 mH

= 44 x ${{10}^{-3}}$ H

${ V }*{ rms }$ = 220 V
Frequency of inductor , v = 50 Hz
Inductive reactance , ${ X }*{ L }$ = 2 $\pi$vL

= 2 x 3.14 x 50 x 44 x ${{10}^{-3}}$

= 13.82 Ω

The rms value of current in the circuit

${ I }

*{ rms }$ =*

${ V }{ rms }$ / Xl = 220 / 13.82 = 15.9 Ω

${ V }

Power absorbed , P = ${ V }_{ rms }$ Irms cos$\phi$

For pure inductive circuit , $\phi$ = 90°

P = 0

Thus, power spent in one half cycle is retrieved in the other half cycle.