2.76g of silver carbonate (at mass of Ag =108) on being heated strongly yields a residue weighing ANS IS 2.16g. BUT HOW DID WE ARRIVE AT THIS ANS?PLS ELABORATE.
2Ag2CO3(s) ----> 4Ag(s) + 2CO2(g) + O2(g)
So, on strogly heating silver carbonate will produce silver.
No of moles of silver carbonate = 2.76 g/ 275.7 = 0.0100
No of moles of Ag = x g/ 108 =
275.7 g of Ag2CO3 produces 108 x 2 g of Ag.
2.76 g will produce = 108 x 2 x 2.76 / 275.7 = 2.16 g of silver.