What is the amount of charge required to carry out the conversion

What is the amount of charge required to carry out the conversion of 1 mole of ${{Al}^{3+}}$ ions to A1 according to the following reaction?
${{Al}^{3+}}$ + ${{3e}^{-}}$ -------> Al
Or
How much charge is required for the following reduction 1 mole of ${{Al}^{3+}}$ to Al?

The number of electrons involved in the reaction is three. It means the conversion of every aluminium ion to aluminium atom requires three electrons.
Therefore, the amount of electricity required for one mole of ${{Al}^{3+}}$ ions
= 3 F or 3 x 96500 C = 289500 C