Using the VSEPR theory identity the type of hybridization and draw the structure of O${{F}_{2}}$. What are oxidation states of O and F?



Electron dot structure of O${{F}{2}}$ is

Thus the central atom (O-atom) has 4 pairs of electrons (2 bond pairs and 2 lone pairs). Hence oxygen in O${{F}
{2}}$ is s${{p}^{3}}$ hybridised and the molecule is v-shaped. Oxidation sTate" of F = - 1, oxidation state of O = + 2.