Molar volume is the volume occupied by 1 mol of any (ideal) gas at standard temperature and pressure (STP: 1 atm pressure, 0°C). Show that it is 22.4 L.

# Molar volume is the volume occupied by 1 mol of any

**prasanna**#2

As, for one mole of ideal gas, pV = µRt

pV = RT

V = RT / p

Putting , R = 8.31 J ${{mol}^{-1}}$ ${{K}^{-1}}$ , T = 273 K

p= 1 atm = 1.013 x ${{10}^{5}}$ N-${{m}^{-2}}$

V = 8.31 x 273 / 1.013 x ${{10}^{5}}$ = 0.0224 ${{m}^{3}}$

= 0.0224 x ${{10}^{6}}$ cc

22400 cc = 22.4L